A fixed coil of wire with 10 turns and an area of 0.055 m2 is placed in a perpendicular magnetic field. This field oscillates in direction and magnitude at a frequency of 10 Hz and has a maximum value of 0.12 T, (a) What is the average emf induced in the coil during the time it takes for the field to go from its maximum value in one direction to its maximum value in the other direction? (b) Repeat part (a) for a time interval of one complete cycle. (c) At what time(s) during a complete magnetic field cycle would you expect the induced emf to have its maximum magnitude? What about its minimum value? Explain both answers

Part a)

Average EMF for half cycle is

Part b)

For one complete cycle we will have

Part c)

Maximum induced EMF will be at

t = 0.025 s and 0.075 s

minimum induced EMF is at

t = 0.05s and 0.1 s

Explanation:

As we know that magnetic field is oscillating in direction as well as magnitude

so induced EMF is given as

Part a)

For average value of EMF from positive maximum to negative maximum which is equal to half cycle

so we have

Part b)

For one complete cycle we will have

Part c)

Maximum induced EMF will be at

here we know

t = 0.025 s and 0.075 s

minimum induced EMF is at

so it is

t = 0.05s and 0.1 s

iron would move it is magnetic there is a mag field around the current in the wire

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.