An object attached to an ideal massless spring is pulled across a frictionless surface. If the spring constant is 45 N/m and the spring is stretched by 0.88 m when the object is accelerating at 0.8 m/s2, what is the mass of the object

Explanation:

Using Hooke's law,

F = -k × delta x

Where,

F = force

k = spring constant

= 45 N/m

Delta x = spring displacement

= 0.88 m

F = 45 × 0.88

= 39.6 N

a = 0.8 m/s^2

Force, F = Mass, M × acceleration, a

M = 39.6/0.8

= 49.5 kg

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