A grasshopper jumps a horizontal distance of 1.00m from rest, with an initial velocity at a 45° angle with respect to the horizontal. a)find the initial speed of the grasshopper

b) find the maximum height reached.
please answer.

At maximum height, kinetic energy is converted in potential energy  formula: at max height, ke = ½ * 0.27kg * (16m/s) ² = 34.56 j  so the remaining pe = (41.70 – 34.56)= 7.14 j = 0.27 kg * 9.8m/s² * h  = (9.8/7.14 * 0.27)so max height h = 5.08 or 5 m