The electric flux through a square-shaped area of side 6 cm near a large charged sheet is found to be 5 ✕ 10−5 N · m2/C when the area is parallel to the plate. Find the charge density on the sheet (in C/m2). (Enter the magnitude.)

Explanation:

Given that,

Side of sheet = 6cm

Electric Flux =

Area of the square sheet, A= 6×6

= 36cm²

= 36×10⁻⁴ m²

Now

the electric flux (Φ) is given as:

where, E = Electric field

substituting the values in the  equation,

Now the charge density (σ) on a sheet is given as:

where, = Permittivity of the free space = 8.85×10⁻¹²

substituting the values in the above equation, we get

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