A resistance of 10 , an inductor of 10/377 henries, and a capacitor of 0.1/377 farads are all connected in series to a 60-hertz, 100-volt source. Determine the magnitude of the current.

The magnitude of the current is 10 A.

Explanation:

Given that,

Resistance, R = 10 ohms

Inductance,

Capacitance,

Voltage, V = 100 V

Frequency, f = 60 Hz  

At resonance condition, the resistance of the circuit is equal to its impedance. It is given by :

Let I is the current. It can be calculated using Ohm's law as :

V = I Z

So, the magnitude of the current is 10 A. Hence, this is the required solution.

i agree kid

explanation:

a

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.