A city’s bus line is used more as the urban population density increases. The more people in an area, the more likely bus lines will be utilized. The population of City A, in Texas, is 29,455 and covers an area of 19.42 mi2. The population of City B, in Alabama, is 34,890 and covers an area of 25.4 mi2. Which city’s residents are more likely to use public buses? Explain

The residents of the city A are more likely to use public buses the city B.

Population density  can be calculated by dividing the total population by the total area of the city.

City A:

Total population - 29455

Total area = 19.42 square miles,

Thus, the population density of the city is 1516.7 people per mile squared.

City B:

Total population = 34890

Total area =  25.4 square miles

Thus, the population density of the city is 1373.6 people per mile squared.

Since, the population density of the of city A is more than the City B.

Therefore, the residents of the city A are more likely to use public buses the city B.

To know more about population density,

link

City A residents

Explanation:

First we need to calculate the population density of each city. This is calculated by dividing the total population by the total area of the city.

City A has 29455 people and 19.42mi2 of area, so the density is 1516.7 people per mile squared.

City B has 34890 people and 25.4 mi2 of area, so the density is 1373.6 people per mile squared.

If the city with bigger people density is more likely to use bus lines, the city A is the one whose people are more likely to use bus lines, as it has a bigger people density.

the answer is 46 mls because when you add the speed per second it increses the speed

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂