Four copper wires of equal length are connected in series. their cross-sectional areas are 0.6 cm2 , 1.9 cm2 , 4.1 cm2 , and 5 cm2 . if a voltage of 126 v is applied to the arrangement, determine the voltage across the 1.9 cm2 wire. answer in units of v.

Therefore the voltage across the 1.9 cm² wire is 25.15 v.

Explanation:

Given that,the four copper wires is connected in series and their length of the copper wire are same.

The cross section area of the wires are 0.6 cm², 1.9 cm², 4.1 cm² and 5 cm².

The resistance of a wire depends the the length of wire, the cross section area of the wire and the resistivity of the wire.

R = resistance of a wire

= resistivity of the wire

l = length of the wire

A= cross section area of the area.

Let the length of the wires be l and resistivity be .

If the resistance connects in series, then the total resistance

R=R₁+R₂+R₃+....

Here the length of the wires and the resistivity of the wires are same for all wire, but the cross section areas are different for each of them

,  , and

Therefore the total resistance

 [ 10000 multiply convert cm² to m²]

     ohm

The voltage of 126 v is applied to the arrangement.

Ohm's Law:

I= current

R= resistance

V= voltage

Therefore the current passes through the circuit

  A

The voltage across the 1.9 cm² is

  ≈25.15 V

Therefore the voltage across the 1.9 cm² wire is 25.15 v.

answer: the correct answer id option(d).

explanation:

snell's law refraction:

the angle of refraction =

the angle of incidence =

refractive index of air = = 1

refractive index of glycerol = 1.47

from the given options, the most closest answer to 63.72° is 65° of option (d).

i don't understand is there any other way you can rephrase it plz let me know in the comments and i will do it.

explanation: