If the resulting trajectory of the charged particle is a circle, what is , the angular frequency of the circular motion?Express in terms of ,w, m and B0 .

ω = B₀q/m

Explanation:

The centripetal force on the charge equal the magnetic force on the charge. (Since the trajectory is a circle). So, mrω² = B₀qv.

v = rω The speed of the charge and r = radius of path

mrω² = B₀qrω

ω = B₀q/m

The angular frequency ω = B₀q/m

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