Samuel is running in a park’s nature trail. At the first checkpoint, he ran 925 m in 10 minutes. At the second checkpoint, he slowed down and only ran 673 m in 13 minutes. What was the average velocity of Samuel’s entire trip (in m/s)? (1 point)

The average velocity of Samuel’s entire trip is 1.16 m/s.

Explanation:

Given:

Distance covered at first checkpoint (d₁) = 925 m

Distance covered at second checkpoint (d₂) = 673 m

Time taken for reaching first checkpoint (t₁) = 10 min = 10 × 60 = 600 s [∵1 min = 60 s]

Time taken for reaching second checkpoint (t₂) = 13 min = 13 × 60 = 780 s

Now, the average velocity of Samuel's entire trip is given by the formula:

Total distance traveled is equal to the sum of the distances traveled at first and second checkpoints. So,

Total distance covered =

Total time taken =

Therefore, the average velocity is given as:

Hence, the average velocity of Samuel’s entire trip is 1.16 m/s.

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.