A body initially at rest, starts moving with a constant acceleration of 2ms-2 .calculate the velocity acquired and the distance travelled in 5s

a) 10 m/s

b) 25 m

Explanation:

a)

The body is moving with a constant acceleration, therefore we can solve the problem by using the following suvat equation:

where

u is the initial velocity

v is the final velocity

a is the acceleration

t is the time

For the body in this problem:

u = 0 (the body starts from rest)

is the acceleration

t = 5 s is the time

So, the final velocity is

b)

In this second part, we want to calculate the distance travelled by the body.

We can do it by using another suvat equation:

where

u is the initial velocity

v is the final velocity

a is the acceleration

s is the distance travelled

Here we have

u = 0 (the body starts from rest)

is the acceleration

v = 10 m/s is the final velocity

Solving for s,

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.