Calculate the current required to create a 0 .85-mT magnetic field at the center of a loop of wire of diameter 12 cm

81.2 A

Explanation:

The magnetic field at the center of a current-carrying loop is given by

where

is the vacuum permeability

I is the current in the loop

R is the radius of the loop

In this problem, we have:

d = 12 cm is the diameter of the loop, so its radius is

R = d/2 = 12/2 = 6 cm = 0.06 m

is the magnetic field at the center

Therefore, the current in the loop must be:

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