A morsel of food with a mass of 3.8 g is injected into the esophagus with an initial speed of 2.2 cm/s. On the way down to the stomach, the walls of the esophagus exert an upward resistive force of 2.7 ✕ 10-3 N on the morsel. If the esophagus is 19.4 cm long, with what speed does the morsel of food enter the stomach?

Explanation:

mass  m = 3.8 g

= 3.8 x 10⁻³ kg

force = 2.7 x 10⁻³N

acceleration = - 2.7 x 10⁻³ / (3.8 x 10⁻³)

a =-  .7105 m /s²

= 71.05 cm/s²

v² = u² - 2 a s

= 2.2² - 2 x 71.05 x 19.4

= 4.84 - 2756.74

= - 2751.9

= - 2752 cm /s

Since it is negative that means , resistive force will not allow it to enter esophagus . It will be going in upward direction.

It appears that there is something wrong with given data.

i dont think you are wrong for wanting to get even with someone who did you wrong.

(i'm an eye for an eye kind of person) but if this person hurt you in a sexual way, i dont suggest doing anything to him. he should be taken to the proper authorities, you could go to jail depending on what you do. if it was something small like your sibling took your spot on the couch, than yea, i would get even with him by taking one of his favorite snacks lol. but i dont suggest you doing anything illegal.

the answer is a 3.8cm

explanation: