Suppose Person A is traveling on a spaceship going 50% of the speed of light. Person A measures the length of the spaceship to be 10 meters. How long would a Person B measure the spaceship if person B were on a planet as the spaceship passed by?

L = 8.66 m

Explanation:

The length measured by the moving observer is related to the true length is given by

L = L₀ √1 - (v²/c²)

Where L₀ is the length of the spaceship as measured by person A, v is the speed of spaceship of person A and c is the speed of light c = 3.8x10ᵃ m/s

L = 10√1 - (0.5c)²/c²

L = 10√1 - (0.5*3.8x10ᵃ)²/3.8x10ᵃ ²

L = 8.66 m

Therefore, the Person B would measure the spaceship length to be 8.66 m

answer; (arch); good luck

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14