A circular coil that has N = 230 turns and a radius of r = 10.0 cm lies in a magnetic field that has a magnitude of B 0 = 0.0650 T directed perpendicular to the plane of the coil. What is the magnitude of the magnetic flux Φ B through the coil?

Φ = 0.469 Wb

Explanation:

Given,

N = 230 turns

Radius, r = 10 cm

Magnetic field, B = 0.0650 T

Magnetic flux  = ?

now,

Φ = NBA

Φ = 230 x 0.0650 x π x r²

Φ = 230 x 0.0650 x π x 0.1²

Φ = 0.469 Wb

Hence, the magnetic flux is equal to Φ = 0.469 Wb

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

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