My Notes (a) A 41 Ω resistor is connected in series with a 6 µF capacitor and a battery. What is the maximum charge to which this capacitor can be charged when the battery voltage is 6 V? (When entering units, use micro for the metric system prefix µ.)

Explanation:

The give data is as follows.

             C = 6 =

             V = 6 V

Now, we know that the relation between charge, voltage and capacitor for series combination is as follows.

              Q = CV

                  =

                  =

or,               = 36

Thus, we can conclude that maximum charge of the given capacitor is 36 .

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because if the tool that you are using is not balanced it there would be false mass.