Elevators decelerate to stop at a floor. During the deceleration of an ascending elevator, the normal force on the feet of a passenger is her weight. During the deceleration of a descending elevator, the normal force on the feet of a passenger is her weight.

During the deceleration of an ascending elevator, the normal force on the feet of a passenger is greater than her weight.

During the deceleration of a descending elevator, the normal force on the feet of a passenger is less than her weight.

Explanation:

Normal force on her feet is the upward force due to gravitational force acting downwards.

During the deceleration of an ascending elevator, the normal force on the feet of a passenger is greater than her weight. This is because the elevator is moving upwards although the acceleration is reducing.

During the deceleration of a descending elevator, the normal force on the feet of a passenger is less than her weight. This is because the elevator is moving downwards although the acceleration is reducing.

hypothesising or postulating

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards