An incident beam of light moves through liquid water ( 1.33) and impinges upon an interface with glass ( 1.52) with an angle of incidence of 47.0o. What is the angle of the refracted beam (i. e., in the glass) with respect to the surface normal

The angle of the refracted beam with respect to the surface normal is .

Explanation:

The direction of a beam of light changes when it crosses the interface between two media with different index of refraction. We will consider that n₁ and n₂ are the index of refraction of the first and the second medium and θ₁  and θ₂ are the angles that the beam of light makes with the surface normal in the first and the second medium respectively.

Snell's Law relates the angle of incidence θ₁ and the angle of refraction θ₂ of a beam of light with the index of refraction in each medium:

We are told that:

if we rearrange the equation:

we get an expression for the angle of the refracted beam:

replacing the values we get that:

finally we get that:

potential energy is directly proportional to height.

more height = more potential energy.

greatest increase in height = greatest increase in potential energy

where are the points with the greatest increase in height ?

has to be c-e or d-e .

wavelength divides in half and speed stays the same.