A person walks into a room that has two flat mirrors on opposite walls. The mirrors produce multiple images of the person. Consider only the images formed in the mirror on the left. When the person is 5.80 m from the mirror on the left wall and 6.10 m from the mirror on the right wall, find the distance from the person to the first three images seen in the mirror on the left wall.

Image1-11.6m

Image2-23.8m

Image3-35.4m

Explanation:

The distance from the images can be found by adding up the length of the light path from the observers eye.

#For image I:

Hence, distance from image one is 11.6m

#For image II:

Hence, distance from image two is 23.8m

#For image III:

Hence, distance from image three is 35.4m

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .