Coherent light with wavelength = 600 nm falls on two very narrow closely spaced slits and the interference pattern is observed on a screen that is 4 m from the slits. Near the center of the secreen the separation between adjacent maxima is 2 mm. What is the distance between the two slits?

The distance between the two slits is 1.2mm.    

Explanation:

The physicist Thomas Young establishes, through its double slit experiment, a relationship between the interference (constructive or destructive) of a wave, the separation between the slits, the distance between the two slits to the screen and the wavelength.

 (1)

Where is the distance between two adjacent maxima, L is the distance of the screen from the slits, is the wavelength and d is the separation between the slits.  

If light pass through two slits a diffraction pattern in a screen will be gotten, at which each bright region corresponds to a crest, a dark region to a trough, as consequence of constructive interference and destructive interference in different points of its propagation to the screen.  

Therefore, d can be isolated from equation 1.

 (2)

Notice that it is necessary to express L and in units of millimeters.

⇒

⇒

Hence, the distance between the two slits is 1.2mm.

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if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.