In a fast-pitch softball game the pitcher is impressive to watch, as she delivers a pitch by rapidly whirling her arm around so that the ball in her hand moves in a circle. In one instance, the radius of the circle is 0.610 m. At one point on this circle, the ball has an angular acceleration of 67.6 rad/s2 and an angular speed of 17.0 rad/s. (a) Find the magnitude of the total acceleration (centripetal plus tangential) of the ball. (b) Determine the angle of the total acceleration relative to the radial direction.

(a) 181.05 m/s²

(b) 13.2°

Explanation:

Given:

Radius of the circle (R) = 0.610 m

Angular acceleration (α) = 67.6 rad/s²

Angular speed (ω) = 17.0 rad/s

(a)

Radial acceleration of the ball is given as:

Plug in the given values and solve for . This gives,

Now, tangential acceleration is given by the formula:

Plug in the given values and solve for . This gives,

Now, the magnitude of total acceleration is given as the square root of the sum of the squares of tangential and centripetal accelerations. Therefore,

Plug in the given values and solve for total acceleration, . This gives,

Therefore, the magnitude of total acceleration is 181.05 m/s².

(b)

Angle of total acceleration relative to radial direction is given by the formula:

Therefore, the total acceleration makes an angle of 13.2° relative to radial direction.

answer: a) y=-8x+5

a) m= -8

b) m= -2

c) m= 7

d) m= 6