The density of ice is 917.what fraction of the volume of a piece of ice will be above the liquid when floating in fresh water

of that piece of ice would be above the freshwater.  Assumptions:

Explanation:

The volume of that chunk of ice can be split into two halves: volume above water , and volume under water . The mass of the whole chunk of ice would be:

.

Let be the acceleration due to gravity. The gravity on the entire chunk of ice would be

.

On the other hand, the size of buoyant force on an object is equal to the weight of the liquid that it displaces. That is: .

Recall that is the volume of the ice above the water, and is the volume of the ice under the water.

The mass of water displaced would be equal to:

.

The weight of that much water would be

.

Apply the equation . The bouyant force on this chunk of ice would be equal to .

Since the ice is floating, the forces on it need to be balanced. In other words, .

On the other hand, recall that

.

Combine the two halves to obtain:

.

.

Divide both sides by (assume that ) to obtain:

.

Rearrange to obtain:

.

However, the question is asking for , the fraction of the volume above water. Note that

.

Therefore,

.

That's equivalent to .

snell's law

refractve index = sin incidence / sin refraction