2) Suppose you have a 120.0-kg wooden crate resting on a wood floor, with coefficient of static friction 0.500 between these wood surfaces. (a) What maximum force can you exert horizontally on the crate without moving it? (b) If you continue to exert this force once the crate starts to slip, what will its acceleration then be? The coefficient of sliding friction is known to be 0.300 for this situation

Explanation:

Given data

Mass m=120.0 kg

Coefficient of static friction

The coefficient of sliding friction

For Part (a) Maximum force

According to Newtons second law the net force aced on the body is given by

The friction force is given by

Conclude that

For Part (b) Acceleration

The acceleration due to dynamic friction is given by:

The dynamic friction is given by:

So the acceleration given by

0.3x0.21x0.08kg=mass 1 sheet

mass 500 = 500xmass 1

volume pile = 0.3x0.2x0.048

density=mass/volume= 500xmass 1/0.3x0.2x0.048

v patient student

probably not the "magnets"in the magnet, so to speak, are thought to be electrons orbiting in shells. vurrent loops two sides to the loop