A hole is to be drilled in the plate at A. The diameters of the bits available to drill the hole range from 12 to 24 mm in 3-mm. increments. Determine: (a) the diameter d of the largest bit that can be used if the allowable load at the hole is not to exceed that at the fillets.

The maximum load is when the hole size is 12 mm so the largest bit such that the load is not exceeding the P value is 12 mm.

Explanation:

As the question is not complete, the complete question is found online and is attached herewith.

From the given data

Allowable stress is given  as

Diameters of the bits are 12 mm, 15 mm, 18 mm, 21 mm, 24 mm

For the fillet, the dimensions are given in the attached question which are as

radius rf=9 mm

Small diameter d=75 mm

Large Diameter D=112.5 mm

The ratios of the diameters are calculated as

D/d=1.5

rf/d=0.12

So for these values and from the table, the value of K is found as 2.1

The area is given as

A=d*t

where d=75 mm, t=12 mm

A=75*12=900x10^-6 m2

Now the value of the average stress is given as

So for the various holes the value of r is the radius of the hole so

D=112.5 mm as given above whereas

d=D-2r

so the areas, value of k and respective values of P and σ are calculated for each radii and are attached with the solution.

As seen from the attached values, it is observed that the maximum load is when the hole size is 12 mm so the largest bit such that the load is not exceeding the P value is 12 mm.

d.7.5cm is your answer

3.2x10^7