Estimate the average force exerted by a shot-putter on a 7.0-kg shot if the shot is moved through a distance of 2.2 m and is released with a speed of 12 m/s .

229.11 N

Explanation:

Mass of the shot (m) = 7.0 kg

Distance moved by the shot (S) = 2.2 m

Initial velocity of the shot (u) = 0 m/s (assume)

Final velocity of the shot (v) = 12 m/s

First we will determine the acceleration of the shot using the following equation of motion.

So, the acceleration of the shot is 32.73 m/s².

Now, using Newton's second law, the force acting on the shot is equal to the product of mass and acceleration. So,

Force = Mass × Acceleration

Therefore, the average force exerted by the shot-putter is 229.11 N.

there is no correct list among the choices you've provided.

the list might look something like this:

-- baby human

-- piccolo

-- flute

-- soprano singer

-- trumpet

-- tenor singer

-- trombone

-- baritone singer

-- baritone horn

-- bass singer

-- tuba

since i had to make up the list myself, i made it easy on myself, and i didn't try to shuffle the string instruments and woodwinds into it too.

answer///scientific method;