To learn to apply the concept of current density and microscopic Ohm's law. A "gauge 8" jumper cable has a diameter ddd of 0.326 centimeters. The cable carries a current III of 30.0 amperes. The electric field EEE in the cable is 0.062 newtons per coulomb. Part APart complete Part B What electric field E′E′E' would have been required to create a current of 30.0 amperes in a copper "gauge 10" wire with diameter ddd equal to 0.259 centimeters?

Consider a uniformly charged ring in the xy plane, centered at the origin. the ring has radius a and positive charge qdistributed evenly along its circumference. a)what is the direction of the electric field at any point on the z axis? . b)what is the magnitude of the electric field along the positive z axis? use k in your answer, where k=14πϵ0. d)the ball will oscillate along the z axis between z=d and z=−d in simple harmonic motion. what will be the angular frequency ω of these oscillations? use the approximation d≪a to simplify your calculation; that is, assume that d2+a2≈a2. express your answer in terms of given charges, dimensions, and constants