The force on a particle is directed along an x axis and given by F = F0(x/x0 - 1) where x is in meters and F is in Newtons. If F0 = 1.2 N and x0 = 3.3 m, find the work done by the force in moving the particle from x = 0 to x = 2x0 m.

0 j

Explanation:

Work done from point p1 to point p2 is given by

Work = ∫ F.dr

Here we are given

F= F₀ (x/x₀ -1)

F₀=1.2 N

x₀=3.3 m

dr= dx (since distance changes along x-axis only)

We will calculate above integral between given points x=0 and x= 2x₀

Putting value of F  , x₀ and  dr

==> Work = ∫ F₀ (x/x₀ -1)

=∫ 1.2 (x/3.3 - 1) dx

= 1.2 /3.3

=∫(x-3.3)dx

=0.363636∫(x-3.3)dx

=0.363636 [ x²/2 - 3.3x]

we are given lower point value x= 0

upper point value x= 2 x₀ = 2× 3.3 = 6.6

putting lower and upper point values of x

= 0.363636 [ {0²/2-3.3(0)} - { (6.6)² /2 - 3.3 × 6.6}]

=0.363636 [ {0}- {43.56 /2 - 21.78}]

=0.363636 [ -{0}]

=0.363636 [0]

=0 j

i-e work is zero joules or no work !

the moon affects the earth gravitation ally, causing certain motions of that body and also producing tides in its ocean and atmosphere. the tidal wave in our atmosphere is, however, far too minute to be an effective cause in any known meteorological phenomenon.

explanation:

come closer and become far apart and become steam/gas