A 50-turn circular wire loop has a radius 3 cm and is located in a uniform magnetic field. The magnetic field lines are perpendicular to the plane of the circular loop. Suppose that the magnetic field is varied so that BBB increases from 0.1 T to 0.35 T in 1.95 ms. Part A Find the average induced emf in the coil (including sign of the emf). View Available Hint(s)

Average induced emf = - 18.13 V

Explanation:

According to Faraday's law of electromagnetic induction,

Induced emf = - N (dΦ/dt)

Φ = magnetic flux = BA

(dΦ/dt) = A(dB/dt)

Emf = -NA (dB/dt)

Average induced emf = - NA (ΔB/Δt)

N = number of turns = 50 turns

A = Cross sectional Area of the circular loop = πr² = π(0.03)² = 0.00283 m²

ΔB = Change in magnetic field strength = 0.35 - 0.1 = 0.25 T

Δt = 1.95 ms = 0.00195 s

Average induced emf = - (50)(0.00283)(0.25/0.00195)

Average induced emf = - 18.13 V

The minus sign indicates that the average induced emf and the change in magnetic flux have opposite signs.

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this

at right angles to each other