The planet Krypton has a mass of 4 × 1023 kg and radius of 1.1 × 106 m. What is the acceleration of an object in free fall near the surface of Krypton? The gravita- tional constant is 6.6726 × 10−11 N · m2/kg2. Answer in units of m/s2.

Explanation:

From the Newton's Law of Universal Gravitation, we have that the acceleration due to gravitational force near an object of mass M, is given by:

Where g is the acceleration due to gravity, G is the gravitational constant, and R is the distance between the objects.

In this case, we have the given values for planet Krypton:

This means that the acceleration of an object in free fall near the surface of Krypton is of 22.0m/s².

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr