PLS HELP
What is the maximum distance the object traveled between the second and
fourth seconds?

d = 4 [m]

Explanation:

Looking at the graph given to us, we can see that between two and four seconds the body moves two meters towards the negative direction and then returns to the positive direction the same amount of length. Therefore the maximum distance traveled is equal to:

Between the 2 and 3 seconds

- 2 [m]

Between the 3 and 4 seconds

2 [m]

The total displacement

d = 2 + 2

d = 4 [m]

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.

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