If all resistors are rated 1/4 Watt, what power is being dissipated by the resistive network (the resistive network's effective power rating) at the point one or more elements reach their individual rating

Explanation:

Req = 97 ohms

P1 = P2 = P3 = 1/4 watt

P = I2 × R

R2 is in parallel, Rt

1/Rt = 1/R1 + 1/R2

P = V2/R

At constant voltage, Pt = P1 + P2

R2s in series with R1

Req = Rt + R1

P = I2 × R

At constant current, Peq = Pt + P1

Peq = P1 + P2 + P3

= 3/4 W

= 0.75 W

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

It would be c hope this out