A 2,200 kg car moving at 18 m/s hits a barrier and comes to a stop. How much work is done to bring the car to a stop?3.6 x 105J3.6 x 105J4.2 x 105J4.2 x 105J

Explanation:

From the question, mass(m)=2200kg, unitial velocity(u)=18m/s and final velocity(v)=0m/s

We can calculate the work done to bring the car to a stop from the relation;

,where

W=Work done

F=Force

S=distance

Also,

Putting eqn(2) into equn(3) we obatin

From the equation of motion;

and

Substituting these into eqn(3), we obtain;

Substituting the values of m,u and v into the equation, we obtain.

Simplifying, we obtain;

NB: The negative sign indicates that the car decelerated to a stop.

Hence the Work done on the car is

hello there!

your answer is a “generator”

a generator does not create energy but instead it transforms it.

it’s basically a motor working in reverse.

unbalanced force

explanation: