A 120 g block attached to a spring with spring constant 3.0 N/m oscillates horizontally on a frictionless table. Its velocity is 21 cm/s when x0 = -4.1 cm

0.059 m

Explanation:

where k is the spring constant, A is the amplitude, x is the extension of spring, m is the mass of the spring and v is the velocity in m/s. Making a the subject then

By substituting the given values then where m is 0.12 Kg, x= 0.0041 m, v is 0.21 m/s and K is 3 N/m then

the total distance traveled by the car is

30km + 49km = 79 km .