The electric potential difference across the membrane of a body cell is 0.070 V (higher on the outside than on the inside). The cell membrane is 8.0 x 10-9 m thick. Determine the magnitude and direction of the E field through the cell membrane. Describe any assumptions you made

The electric field is and the ditection is from outer to inner side of the membrane.

Explanation:

We know the electric field () is given by , 'V' being the potential.

In 1-D, it can be written as

where 'd' is the separation of space in between the potential difference is created.

Given, and the thickness of the cell membrane is .

Therefore the created electric field through the cell membrane is

1 is a answer of a question