A student wants to make a very small particle accelerator using a 9 V battery. What speed will a proton have after being accelerated from rest through the 9 V potential difference? What speed will an electron have after being accelerated from rest through the 9 V potential difference?

v = 4.15 10⁴ m / s

Explanation:

Suppose that all the energy in the battery is converted into kinetic energy of the proton

            U = K

           q V = ½ m v²

            v = √ 2q V/m

            v = √ (2  1.6 10⁻¹⁹ /1.67 10⁻²⁷  9)

            v = √( 17.2455 10⁸)

            v = 4.15 10⁴ m / s

Relativistic corrections are not needed as this speed is much less than the speed of light

so easy. just google the electromagnetic waves and it’ll pop up.

molecules are free to separate from each other and will take on the shape of the container. molecules move completely at random and high speeds. they vibrate in a fixed position and do not move around much. molecules expand to the edge of their container.