Tarzan swings on a 36.0 m long vine initially inclined at an angle of 31.0◦ with the vertical. The acceleration of gravity if 9.81 m/s 2 . What is his speed at the bottom of the swing if he a) starts from rest? Answer in units of m/s.

  v = 10 m/s

Explanation:

Given,

Length of the vine, l = 36 m

Angle of inclination = 31.0◦ with the vertical

acceleration due to gravity = 9.81 m/s²

Using Conservation of energy

      KE = PE

  v = 10 m/s

Hence, the speed of the swing is equal to 10 m/s

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