Determine the magnitude of the magnetic flux through the south-facing window of a house in British Columbia, where Earth's B⃗ field has a magnitude of 5.8 × 10−5 T and the direction of B⃗ field is 72∘ below horizontal with the horizontal component of B⃗ field directed to the north. Assume the area of the window is 3 m^2 . My main issue is how to setup the field in relation to the window's direction. I get how to calculate using the magnetic flux=area*B*cos(theta), but in my homework, I keep getting told I'm solving for the angle wrong??