A 10-kg mass slides down a flat hill that makes an angle of 10° with the horizontal. If friction is negligible, what is the resultant force on the sled?

The resultant force on the sled is 17.02 N and this can be determined by using Newton's second law of motion

Given :

A 10-kg mass slides down a flat hill that makes an angle of 10° with the horizontal.

First, determine the force by using Newton's second law of motion.

F = ma

F = 10 9.8

F = 98N

Now, the resultant force on the sled can be calculated as:

Now, substitute the known terms in the above expression.

Simplify the above expression in order to determine the value of .

= 17.02 N

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Resultant force = 17.02 N

Explanation:

As we assume the coefficient of friction is negligible, the normal force won't affect the resultant force.

As a result of this, the sine of the angle times the force of gravity on the 10 kg mass is equal to the resultant force, which is, force due to gravity = m × a = 10 kg × 9.8 m/s² = 98 N

98 sin(10)=?

Sin(10)= 0.1736

98 x 0.1736= 17.02 N.

Therefore, the resultant force = 17.02 N

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