As a protest against the umpire's calls, a baseball pitcher throws a ball straight up into the air at a speed of 19.0 m/s. In the process, he moves his hand through a distance of 1.10 m. If the ball has a mass of 0.150 kg, find the force he exerts on the ball to give it this upward speed.

Explanation:

Given data

Initial speed vi=0 m/s

Final speed vf=19.0 m/s

Δy=1.10 m

Mass of ball m=0.150 kg

To find

Force

Solution

First we need to find acceleration of the ball.So we can apply:

vf²=vi²+2aΔy

vf²=0+2aΔy

Because we get the acceleration of the ball.We can now find the force the players exerts on the ball by using Newtons second law

∑F=F.player -mg=ma

the answer is b ) square root of 5