Water vapor is cooled in a closed, rigid tank from T1 = 480°C and p1 = 100 bar to a final temperature of T2 = 320°C. Determine the final specific volume, v2, in m3/kg, and the final pressure, p2, in bar.

v1 = v2 = 0.0347m³/kg the tank is rigid (constant volume)

P2 = 78.8bar

Explanation:

Assuming ideal gas behavior, the relationship holds for the water vapor

PV = RT/M

Where P = pressure in the tank

V = Specific volume in m³/kg

R = gas constant = 8.314 J/mol•K

T = absolute temperature in K

M = molar mass in kg/mol

The detailed solution steps can be found below in the attachment.

V2 = V1 because the tank is rigid so it is a constant volume process. Also at the final temperature the water molecules are still in the gaseous phase so V2 is still the same as v1.

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answer: the metamorphic rocks are formed when they are exposed to high pressure and high temperatures. this happens when one of the earth's plates comes in contact with the other plate by traveling in opposite directions, straight into each other or slipping under one another. the friction that is caused by this activity results in   melting of rocks and when it cools they are known as metamorphic rocks. this process needs a controlled amount of pressure and temperature otherwise it may turn into magma.