A diver makes 0.50 revolutions on the way from a 9.4-m-high platform to the water. Assuming zero initial vertical velocity, find the diver's average angular velocity during a dive.

Explanation:

wi = 0 rad/s

Theta = 0.5 rev

r = 9.4 m

S = 2 × pi × theta × r

= 2pi × 0.5 × 9.4

= 29.53 m

at × r = g

= 1.043 rad/s^2

Using angular equation of motion,

wf^2 = wi^2 + 2× at × S

wf^2 = 2 × 1.043 × 29.53

= 7.85 rad/s

im guessing the west of station b

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.