A locomotive is accelerating at 3.08 m/s2. It passes through a 20.8-m-wide crossing in a time of 2.93 s. After the locomotive leaves the crossing, how much time is required until its speed reaches 29.4 m/s?

Required time t=5.8s

Explanation:

Given data

Acceleration a=3.08 m/s²

Speed v=29.4 m/s

Required

How much time t is required

Solution

As the train passes through the crossing its motion is described by:

Substitute the given values

So

So time required can be calculated by:

Required time t=5.8s

i am pretty sure it is c because when people are closer together, they cannot move as freely. picture being in a mostly full elevator, for instance. the people are right next to you, and you can barely move.