What is approximate resistance between P and Q?
a) 0.5
b)0.8
c)2.0
d)2.2
e)3.6

0.5 Ohms

Explanation:

We note that the node Q is also between the resistors of 1ohm and 2ohms.

We note that the node P is also between the resistors of 2ohms and 3ohms.

Thus, all these resistors are in parallel, beween nodes P and Q

1/Re=1/R1+1/R2+1/R3

1/Re=1/1+1/2+1/3=(6+3+2)/6=11/6 [ohm^(-1)]

Re=6/11=0.54ohms

Rounding to the tenth: Re=0.5 ohms

it may be wrong but i think its a

explanation:

considering the bohr theory, the type of connection that requires the transfer the answer conuldn't be right