One mole of nickel (6 1023 atoms) has a mass of 59 grams, and its density is 8.9 grams per cubic centimeter, so the center-to-center distance between atoms is 2.23 10-10 m. You have a long thin bar of nickel, 2.7 m long, with a square cross section, 0.08 cm on a side. You hang the rod vertically and attach a 67 kg mass to the bottom, and you observe that the bar becomes 1.39 cm longer. From these measurements, it is possible to determine the stiffness of one interatomic bond in nickel.

44 N/m

Explanation:

Finding the interatomic spring stiffness

Because in our model all the bonds are assumed to be the same, the interatomic spring stiffness ks, interatomic is determined by adding the springs . The details of that addition are below, but the final result is that the interatomic spring stiffness is related to the spring stiffness of the wire like so:

Find the attached file for solution

the focus of lesson 1 is newton's first law of motion - sometimes referred to as the law of inertia. newton's first law of motion is often stated as. an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

explanation: