An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.80 mm. If a 17.0 V potential difference is applied to these plates, calculate the following: ](a) the electric field between the plateskV/m(b) the capacitancepF(c) the charge on each platepC

(a) E=9.44×10³ V/m

(b) C=3.74pF

(c) Q=63.6pF

Explanation:

For Part (a)

The electric field between the plates is found by:

E=ΔV/d

Substitute  the given values

So:

For Part (b)

The capacitance of parallel plate capacitor found from:

C=(∈₀A)/d

Substitute the given values

For Part (c)

The Charge on each plate of capacitor is found by:

Q=CΔV

Substitute the  given values

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.

the force represented by vector a is normal force. if the hockey puck is moving to the right, when it is hit with a significant force by the hockey stick the puck will move off in a different direction. correct on edge.