Two hockey pucks, labeled A and B, are initially at rest on a smooth ice surface and are separated by a distance of 18.0 m. Simultaneously, each puck is given a quick push, and they begin to slide directly toward each other. Puck A moves with a speed of 1.30 m/s, and puck B moves with a speed of 1.70 m/s. What is the distance that puck A covers prior to the collision?

pick A moves 10.2 metre

Explanation: since they were given a quick push simultaneously the product of their distance moved and velocity would be equal.

Let the distance moved by puck B x then that of puck A would be 18-x.

So therefore we have that,

1.3*(18-x) = 1.7*x

23.4 - 1.3x = 1.7x

23.4=3x

Making x subject of formula we have

x = 23.4/3 = 7.8m

But the distance moved by puck A is 18-x. So therefore,

18-7.8=10.2meter

i dont know but

explanation:

whoever your teacher is, deserves a raise for using pokemon as an example