What happens when both sides of the tug of war rope or equal in force? What is the net force in this scenario?

0

Explanation:

The net force=0

Explanation:

Tug of war is a game where by there are two sides pulling a rope. So, if both sides applied equal forces. I.e both of them are pulling with same same Force.

Force from team 1 = F1

Force from team 2 = F2

Then, F1 = F2 = F

So, if this happens we expect none of the teams to win, and then the body will be in equilibrium, so no acceleration.

Then net force will be zero

Since from newton second law

Fnet = ma

Since the body is in equilibrium, then a = 0

Then, Fnet = 0 N

So the net force is zero.

Or

Summation of force acting on the rope

Fnet = F1 — F2

They are opposite forces, then one of them have to be negative

Since F1 = F2 = F

Fnet = F-F

Fnet = 0 N

answer: the rock sample is a sedimentary rock.

explanation:

it is given that:

mass of rock sample, m = 2.7 g

volume of rock sample,

so, density of rock sample will be

since, the density of rock sample is . hence, the rock sample is a sedimentary rock, whose densities varies between .

at positions a, g kinetic energy is maximum.

at position d, potential energy is maximum.