In an isochoric process, the pressure in a system changes from 10 kPa to 20 kPa at V= 5m3. Calculate the work done in this process according to the sign convention in the class.

work done in the process is 0 J.

Explanation:

Given :

Initial pressure of system ,

Final pressure of system ,

Volume of system ,

We know, In thermodynamics work done is defined as :

Here , P is pressure and is change in volume.

Now, coming back to question , it state that the process is isochoric .

Therefore, change in volume ,

Putting value of in above equation we get ,

W = 0 J.

Therefore , work done in this process is 0 J.

Hence, this is the required solution.

0.11 m/s and 0.28 m/s should be correct