You have a circular loop of current carrying wire in a large uni-form magnetic field. Because it’s a current carrying loop in a magnetic field, there will be a torque acting on it. Your friend wants to increase the torque by doubling the loop over on itself, so that it now makes two circular loops on top of each other by using the same length of wire. What is the new torque in terms of the old torque?

Torque(τ) = NIABsinθ

Explanation:

Motors have loops of wire in a magnetic field. When current is passed through the loops, the magnetic field exerts torque on the loops, which rotates a shaft.

If we have a multiple loop of N turns, we get N times the torque of one loop. Finally, note that the area of the loop is A = wl; the expression becomes

Torque(τ) = NIABsinθ

Where N = number of turn of the loop

I = current

A = area

B = magnetic field.

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.