A 3.00 µF and a 5.00 µF capacitor are connected in series across a 30.0 V battery. A 10.00 µF capacitor is then connected in parallel across the 3.00 µF capacitor. Determine the voltage across the 10.00 µF capacitor.

Hence,

The voltage across the 10.00 µF capacitor is 18.75 Volts.

Explanation:

Given:

A 3.00 µF and a 5.00 µF capacitor are connected in series across a 30.0 V battery,

V = 30.0 V

To Find:

V₁  = ? (voltage across the 10.00 µF capacitor)

Solution:

For Capacitor Series Combination we have,

Substituting the values we get

As Capacitors are connected in series they have the same charge on each plates, and is given by,

Substituting the values we get

Also in Series voltage will be different across C₁ and C₂,

Therefore voltage across C₁  will be

Substituting the values we get

Now according to the given condition,

10.00 µF capacitor is then connected in parallel across the 3.00 µF capacitor,

Therefore we know in Parallel, Voltage remain Same, Hence Voltage across 10.00 µF capacitor will be same as that of voltage across V₁.

Hence,

The voltage across the 10.00 µF capacitor is 18.75 Volts.

  the unit of the measure =

explanation:

  the property that is quantified by the energy needed per of material to raise the temperature by one.

  si unit of energy = joule (j)

  si unit of temperature = kelvin (k)

  si unit of mass of material = kilogram (kg)

the property that is quantified by the energy needed per of material to raise the temperature by one is called specific heat.

the unit of specific heat is