A bullet is accelerated down the barrel of a gun by hot gases produced in the combustion of gun powder. What is the average force (in N) exerted on a 0.0500 kg bullet to accelerate it to a speed of 625 m/s in a time of 1.10 ms (milliseconds)

28409.1 N

Explanation:

Force: This can be defined as the product of mass and acceleration. The S.I unit of force is Newton(N).

From the question,

F = maEquation 1

Where F = force exerted on the bullet, m = mass of the bullet, a = acceleration of the bullet.

But,

a = v/t Equation 2

Where v = velocity,t = time.

Substitute equation 2 into equation 1

F = m(v/t) Equation 3

Given: m = 0.05 kg, v = 625 m/s, t = 1.1 ms = 0.0011 s.

Substitute into equation 3

F = 0.05(625)/0.0011

F = 28409.1 N

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